Answered. IN THE GIVEN FIGURE, DB IS PERPENDICULAR TO BC, DE IS PERPENDICULAR TO AB AND AC IS PERPENDICULAR TO BC. PROVE THAT BE/DE= AC/BC. 2. See answers. report flag outlined. bell outlined. Log in to add comment.
in the given figure, db is perpendicular to bc, de is perpendicular to ab and ac is perpendicular to bc. prove that be/de= ac/bc.
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Click here??to get an answer to your question ? The perpendicular from A on side BC of a ? ABC intersect BC at D such that DB = 3CD . Prove that 2AB^2 = 2AC^2 + BC ^2, 4/1/2020 · In the adjoining figure , two line segments AC and BD intersect each other at the point P such that PA = 6 cm, PB = 3 cm, PC = 2.5 cm, PD = 5 cm, ?APB = 50° and ?CDP = 30°. Then, ?PBA is equal to, 14. The perpendicular from A on side BC of a ? ABC intersects BC at D such that DB = 3CD (see Figure). Prove that 2AB 2 = 2AC 2 + BC 2. Solution: Given, the perpendicular from A on side BC of a ? ABC intersects BC at D such that; DB = 3CD. In ? ABC, AD ?BC and BD = 3CD. In right angle triangle, ADB and ADC, by Pythagoras theorem,, [Since DE || BC ? ADE = ? B (Corresponding angles)] and, ? A = A [Common] ADE ~ ABC. Therefore, (area of ADE / area of ABC) = (AD 2 /AB 2) In the figure, PB and QA are perpendicular to segment AB. If OA = 5 cm, PO = 7cm and area (?QOA) = 150 cm 2, find.
Question 26: Assertion: In the given figure , ?ABC is given with AB = AC and BA is produced to D such that AB = AD.Then, ?BCD = 90°. Reason: In the given figure AB = AC and D is a point on BC produced. Then, AB > AD. (a) Both Assertion and Reason are true and Reason is a correct explanation of Assertion. (b) Both Assertion and Reason are true but Reason is not a correct explanation of …
In the adjoining figure (not drawn to scale), PS = 4 cm, SR = 2 cm, PT = 3 cm and QT = 5cm. (i) Show that DPQR ~ DPST. (ii) Calculate ST, if QR = 5·8 cm. 10. In the given figure , ABPQ and ACPR. Prove that BCQR. 11. In the given figure , AB and DE are perpendicular to BC . If AB = 9 cm, DE = 3 cm and AC = 24 cm, calculate AD. 12. In the given …
8/9/2018 · In the figure given, Question 4. In the adjoining figure , AB=AC and AD is median of ?ABC, then AADC is equal to (a) 60° (b) 120° (c) 90° (d) 75° Solution: Question 5. In the adjoining figure , O is mid point of AB. If ?ACO = ?BDO, then ?OAC is equal to (a) ?OCA (b) ?ODB (c) ?OBD (d) ?BOD Solution: Question 6. In the adjoining …
